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In the following question, select the odd letters from the given alternatives.

ABEHK

BJMPS

CPSVY

DEHKM

Answer:

D. EHKM

Read Explanation:

1) BEHK → B + 3 = E; E + 3 = H; H + 3 = K

2) JMPS → J + 3 = M; M + 3 = P; P + 3 = S

3) PSVY → P + 3 = S; S + 3 = V; V + 3 = Y

4) EHKM → E + 3 = H; H + 3 = K; K + 2 = M

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