Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.

Conditions:

• (i) If the first element is a symbol and the last, a number, the codes for these two are to be interchanged.

• (ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as $\emptyset$.

• (iii) If both second and third elements are either numbers or symbols, the third element is to be coded as the code for the second element.

  How will '% + < 2 5 =' be coded?

• A. LPHMBJ
• B. LHHMBJ
• C. LPPMBJ
• D. JHPMBL

Answer 1

Answer:

C. LPPMBJ

1. Find the Base Codes from the Table:
   Let's find the direct letter code for each element in the sequence % + < 2 5 =:

   • % $\rightarrow$ L

   • $\rightarrow$ P

   • < $\rightarrow$ H

   • 2 $\rightarrow$ M

   • 5 $\rightarrow$ B

   • = $\rightarrow$ J

   Base Code Sequence: L P H M B J

2. Check the Conditions:

   • Condition (i): The first element (%) is a symbol, but the last element (=) is also a symbol (not a number). This condition does not apply.

   • Condition (ii): The first element is a symbol, not an odd number. This condition does not apply.

   • Condition (iii): The second element (+) and third element (<) are both symbols. Therefore, this condition applies, meaning the third element must take the code of the second element (P replaces H).

3. Apply the Change:

   • Replacing the third letter transforms L P H M B J into L P P M B J.

The correct code combination for '% + < 2 5 =' is L P P M B J.