Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.

Number/Symbol	8	=	4	7	@	%	>	2	!	?	5	3	<	9
Code	Z	F	T	J	D	H	E	X	V	W	K	U	P	A

Conditions:

(i) If the first element is a symbol and the last, a number, the codes for these two are to be interchanged.

(ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as Ø.

(iii) If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.

How will '3 = < 2 @ 8' be coded?

• A. ØPFXDØ
• B. ØFEDXØ
• C. ØFPXDØ
• D. ØFEXDØ

Answer 1

Answer:

C. ØFPXDØ

The correct combination of codes for 3 = < 2 @ 8 is Ø F P X D Ø.

1. Identify the elements:

   • First element: 3 (Odd number)

   • Middle elements: =, <, 2, @

   • Last element: 8 (Even number)

2. Check the conditions:

   • Condition (i): Does not apply because the first element is a number, not a symbol.

   • Condition (ii): Applies. The first element (3) is an odd number, and the last element (8) is an even number. Therefore, both the first and last elements must be coded as Ø.

   • Condition (iii): Does not apply because the second and third elements (= and <) are not perfect squares.

3. Get codes for the middle elements from the table:

   • = → F

   • < → P

   • 2 → X

   • @ → D

4. Combine the results:

   • Replace the first and last elements with Ø, and write the codes for the middle elements as they appear:

   • Ø F P X D Ø