Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.

* (i) If the first element is an odd number and the last element is an even number, the codes for these two (the first and the last elements) are to be interchanged.

(ii) If the second element is a symbol and the fifth element is an even number, the codes for these two (the second and the fifth elements) are to be interchanged.

* (iii) If the third element is a number and the fourth element is a symbol, both these elements (the third and the fourth elements) are to be coded as Y.

Question: 7 6 & 5 8 % 6 2

• A. ATYYDLTS
• B. ATUMDLTS
• C. ADUMTLTS
• D. STUMDLTA

Answer 1

Answer:

B. ATUMDLTS

The correct code combination for the given sequence is ATUMDLTS.

1. Find the Base Codes from the Table:

   • 7 $\rightarrow$ S

   • 6 $\rightarrow$ T

   • & $\rightarrow$ U

   • 5 $\rightarrow$ M

   • 8 $\rightarrow$ D

   • % $\rightarrow$ L

   • 6 $\rightarrow$ T

   • 2 $\rightarrow$ A

   Base Code Sequence: S T U M D L T A

2. Check the Conditions:

   • Condition (i): The first element (7) is an odd number and the last element (2) is an even number. Therefore, this condition applies, and the codes for the first and last elements must be interchanged (S and A swap places).

   • Condition (ii): The second element (6) is a number, not a symbol, so this does not apply.

   • Condition (iii): The third element (&) is a symbol, not a number, so this does not apply.

3. Apply the Change:

   • Interchanging the first and last letters transforms S T U M D L T A into A T U M D L T S.