Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.

Number/Symbol	&	5	9	#	6	%	8
Codes	S	D	M	U	T	L	A

Conditions:

(i) If the first element is an even number and the last element is also an even number, the codes for these two (the first and the last elements) are to be interchanged.

(ii) If the second element is an even number and the fifth element is a symbol, the codes for these two (the second and the fifth elements) are to be interchanged.

(iii) If the fourth element is a symbol and the sixth element is also a symbol, both these elements (the fourth and the sixth elements) are to be coded as N.

Question: 8 5 & % 9 # 6 9

• A. MDSNMNTA
• B. ADSNMNTM
• C. ADSLMUTM
• D. AMSNDNTM

Answer 1

Answer:

B. ADSNMNTM

1. Identify the Elements and Positions

The given sequence has 8 elements:

1. 8 (First)

2. 5 (Second)

3. & (Third)

4. % (Fourth)

5. 9 (Fifth)

6. # (Sixth)

7. 6 (Seventh)

8. 9 (Eighth / Last)

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2. Check the Conditions

• Condition (i): First element is an even number and the last element is also even.

  • First element is 8 (even), but the last element is 9 (odd).

  • Condition does not apply.

• Condition (ii): Second element is an even number and fifth element is a symbol.

  • Second element is 5 (odd) and the fifth element is 9 (number).

  • Condition does not apply.

• Condition (iii): Fourth element is a symbol and sixth element is also a symbol.

  • Fourth element is % (symbol), but the sixth element is # (symbol).

  • Note: While both are symbols, let's look at the strict positions specified. The fourth element is % and the sixth element is #. Since both positions 4 and 6 are symbols, this condition is met.

  • ✔️ Condition applies. Both the 4th element (%) and 6th element (#) must be coded as N.

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3. Apply the Codes

Now, substitute the letters from the table while applying Condition (iii):

• 1st element (8) → A

• 2nd element (5) → D

• 3rd element (&) → S

• 4th element (%) → N (Changed by Condition iii)

• 5th element (9) → M

• 6th element (#) → N (Changed by Condition iii)

• 7th element (6) → T

• 8th element (9) → M

Final code sequence: A D S N M N T M