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In this question, a group of numbers/symbols is coded using letters asper the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.

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Conditions:

(i) If the second element is an odd number and the last element is aneven number, the codes for these two (the second and the last elements)are to be interchanged.

(ii) If the third element is an even number and the fifth element is asymbol, the codes for these two (the third and the fifth elements) are tobe interchanged.

(iii) If the fifth element is a symbol and the sixth element is also a symbol,both these elements (the fifth and the sixth elements) are to be coded as R.

Number/Symbol: E 7 5 % & 4 % 8

AMSDUTLUA

BMADURRUS

CMADUTLUS

DMATUDLUS

Answer:

C. MADUTLUS

Read Explanation:

Applying the coding rules provided, the correct answer is MADUTLUS after following all the conditions for symbol interchange.


Related Questions:

The graph and the table below show the marks obtained by three persons, A, B, and C, in three tests: Test 1, Test 2, and Test 3. If the maximum marks for both Test 1 and Test 2 are 80, and the maximum marks for Test 3 are 100, then how much percentage has A scored more than C considering the performance on all three tests?

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Each of the digits in the number 318924765 is arranged in descending order from left to right. The position of how many digits will remain unchanged as compared to that in the original number?

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.

image.png


Conditions:

  • (i) If the first element is a number and the last, a symbol, the codes for these two are to be interchanged.

  • (ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as $\emptyset$.

  • (iii) If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.

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