Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.

Number/Symbol	^	#	5	7	@	%	>	2	!	?	4	8	$	3
Letter Code	L	F	B	J	D	H	E	X	V	Z	K	U	R	P

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Conditions:

(i) If the first element is a symbol and the last, a number, the codes for these two are to be interchanged.

(ii) If the first element is an odd number, then the first and last elements are to be coded as Ø and ¥, respectively.

(iii) If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.

How will ‘7 # ^ 2 !’ be coded?

• A. JFLX ¥
• B. JBFVZ
• C. ØFLX¥
• D. ØFLXV

Answer 1

Answer:

C. ØFLX¥

The correct code combination for '7 # ^ 2 !' is Ø F L X ¥.

1. Analyze the Elements:

   • First element: 7 (Odd number)

   • Last element: ! (Symbol)

2. Check the Conditions:

   • Condition (i): Does not apply (first element is a number, not a symbol).

   • Condition (ii): Applies, because the first element (7) is an odd number. Therefore, the first element must be coded as Ø and the last element must be coded as ¥.

   • Condition (iii): Does not apply (the second and third elements are symbols, not perfect squares).

3. Apply the Codes from the Table for Middle Elements:

   • # = F

   • ^ = L

   • 2 = X

4. Combine the Final Code:

   • 7 → Ø

   • # → F

   • ^ → L

   • 2 → X

   • ! → ¥