Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.

Conditions:

(i) If the first element is an even number and the last a number, the codes for these two(the first and the last elements) are to be interchanged.

(ii) If the first number is an odd number and the last an even number, the first and last elements are to be retained as it is (i.e first and last elements won't get coded).

Question: 7*%3@6

Number/symbol	4	%	7	3	#	*	9	@	6
Code	X	N	B	J	H	L	Y	F	R

• A. 7LNJF6
• B. BLN3FR
• C. BLNJFR
• D. 7YNJF6

Answer 1

Answer:

A. 7LNJF6

The correct combination of codes for the given sequence is 7 L N J F 6.

Coding Table

• 4 $\rightarrow$ X

• % $\rightarrow$ N

• 7 $\rightarrow$ B

• 3 $\rightarrow$ J

• # $\rightarrow$ H

• * $\rightarrow$ L

• 9 $\rightarrow$ Y

• @ $\rightarrow$ F

• 6 $\rightarrow$ R

Conditions

• (i) Even number first and any number last $\rightarrow$ interchange their codes.

• (ii) Odd number first and even number last $\rightarrow$ keep them uncoded.

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1. Analyze the sequence: The given question sequence is 7 * % 3 @ 6.

2. Check the first and last elements:

   • First element is 7 (an odd number).

   • Last element is 6 (an even number).

3. Apply the matching condition: This perfectly matches Condition (ii).

   • First element 7 remains 7.

   • Last element 6 remains 6.

4. Code the middle elements: Use the table to look up the remaining symbols and numbers:

   • * $\rightarrow$ L

   • % $\rightarrow$ N

   • 3 $\rightarrow$ J

   • @ $\rightarrow$ F

Combining these steps gives the final answer: 7 L N J F 6