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In this question, a group of numbers/symbols is coded using letters asper the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.

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Conditions:

(i) If the second element is an odd number and the last element is aneven number, the codes for these two (the second and the last elements)are to be interchanged.

(ii) If the third element is an even number and the fifth element is asymbol, the codes for these two (the third and the fifth elements) are tobe interchanged.

(iii) If the fifth element is a symbol and the sixth element is also a symbol,both these elements (the fifth and the sixth elements) are to be coded as R.

Number/Symbol: E 7 5 % & 4 % 8

AMSDUTLUA

BMADURRUS

CMADUTLUS

DMATUDLUS

Answer:

C. MADUTLUS

Read Explanation:

Applying the coding rules provided, the correct answer is MADUTLUS after following all the conditions for symbol interchange.


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