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In what time a sum of money becomes 3 times of itself at simple interest rate of 10% per annum?

A18 years

B20 years

C22 years

D24 years

Answer:

B. 20 years

Read Explanation:

Let Principal be ‘p’

A sum of money becomes 3 times of itself,

Amount, A = 3p

SI = A - p = 2p

2p=(p×10×t)100⇒2p=\frac{(p\times{10}\times{t})}{100}

20010⇒\frac{200}{10} = t = 20 years

∴ In 20 years, a sum of money becomes 3 times of itself.


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