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Komal invested a sum of ₹5000 at 20% per annum compound interest, componded annually. If she received an amount of ₹7200 after n years, the value of n is:

A2

B1.4

C2.5

D3

Answer:

A. 2

Read Explanation:

Here's how to solve this compound interest problem:

1. Understand the Compound Interest Formula:

  • A=P(1+R/100)nA = P (1 + R/100)^n

    • A = Amount after n years

    • P = Principal (initial sum of money)

    • R = Rate of interest per annum

    • n = Number of years

2. Set up the equation:

  • A = ₹7200

  • P = ₹5000

  • R = 20%

  • n = ? (what we need to find)

  • Substitute the values into the formula:

    • 7200=5000(1+20/100)n7200 = 5000 (1 + 20/100)^n

3. Solve for n:

  • Divide both sides by 5000:

    • 7200/5000=(1+1/5)n7200 / 5000 = (1 + 1/5)^n

    • 1.44=(6/5)n1.44 = (6/5)^n

    • 1.44=(1.2)n1.44 = (1.2)^n

4. Find the value of n by trial and error or by using logarithms (simpler trial and error in this case):

  • (1.2)1=1.2(1.2)^1 = 1.2

  • (1.2)2=1.44(1.2)^2 = 1.44

5. Conclusion:

  • Therefore, n = 2

The value of n is 2.


Related Questions:

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The compound interest on a certain sum at a certain rate percent per annum for the second year and the third year are ₹ 3300 and ₹ 3630, respectively. The sum is: