Question

Let x be the least number of 4 digits that when divided by 2, 3, 4, 5, 6 and 7 leaves a remainder of 1 in each case. If x lies between 2000 and 2500, then what is the sum of the digits of x?

• A. 15
• B. 4
• C. 9
• D. 10

Answer 1

Answer:

B. 4

LCM of 2, 3, 4, 5, 6 and 7 is 420. Number should be between 2000 and 2500 so, the number is = 420 × 5 = 2100 Remainder will be 1 in each case so the number is = 2100 + 1 = 2101 Sum of digit of the number 2101 is = 2 + 1 + 0 + 1 = 4