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Manoj travels from City A to City B. If Manoj drives his ear at 3/5 of his normal speed, then he reaches City B 10 minutes late. Find the time (in minutes) that Manoj would have taken to travel from City A to City B if he drove at his normal speed.

A17

B11

C24

D15

Answer:

D. 15

Read Explanation:

Let the normal time taken = (t) minutes.

Speed–Time relation

If speed becomes (35)( \frac{3}{5} ) of normal, time becomes:
53×t\frac{5}{3} \times t

Given condition

53t=t+10\frac{5}{3}t = t + 10

Solve

53tt=10\frac{5}{3}t - t = 10
23t=10\frac{2}{3}t = 10

t=10×32=15t = 10 \times \frac{3}{2} = 15
Final Answer: 15 minutes


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