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Manu’s age is 6 times Binus age. 15 years hence Manu will be 3 times as old as Binu find Binu’s age ?

A60 years

B10 years

C45 years

D50 years

Answer:

B. 10 years

Read Explanation:

Let BB be Binu's current age.

Let MM be Manu's current age.

From the problem, we get two equations:

  1. "Manu’s age is 6 times Binu's age"

    M=6BM = 6B

  2. "15 years hence Manu will be 3 times as old as Binu"

    M+15=3(B+15)M + 15 = 3(B + 15)

We can substitute the value of MM from the first equation (M=6BM = 6B) into the second equation:

6B+15amp;=3(B+15)6B+15amp;=3B+45\begin{aligned} 6B + 15 &= 3(B + 15) \\ 6B + 15 &= 3B + 45 \\ \end{aligned}

Now, isolate the term with BB:

6B−3Bamp;=45−153Bamp;=30Bamp;=303Bamp;=10\begin{aligned} 6B - 3B &= 45 - 15 \\ 3B &= 30 \\ B &= \frac{30}{3} \\ B &= 10 \end{aligned}


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