Question

Minimum number of bits essential to store any 2 digit decimal number is equal to

• A. 9
• B. 8
• C. 7
• D. 6

Answer 1

Answer:

C. 7

The correct answer is 7.

• A 2-digit decimal number ranges from 0 to 99 (total of 100 values).

• To represent numbers in binary, $n$ bits can store $2^n$ different values (from $0$ to $2^n - 1$).

• With 6 bits, you can store up to $2^6 - 1 = 63$, which is not enough to reach 99.

• With 7 bits, you can store up to $2^7 - 1 = 127$, which is sufficient to cover all 2-digit decimal numbers up to 99.