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Mohan invests a sum of ₹5400 and Varun invests a sum of ₹9400 at the same rate of simple interest per annum. If, at the end of 6 years, Varun gets ₹480 more interest than Mohan, then find the rate of interest per annum (in percentage).

A4

B2.5

C3

D2

Answer:

D. 2

Read Explanation:

We use the simple interest formula:

SI=P×R×T100SI = \frac{P \times R \times T}{100}

Let the rate = ( R% )

Time ( T = 6 ) years

Difference in principal = ( 9400 - 5400 = 4000 )

Difference in interest = ₹480

So,

480=4000×R×6100480 = \frac{4000 \times R \times 6}{100}

480 = 240R

R=480240=2R = \frac{480}{240} = 2

Answer: 2% per annum


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തന്നിരിക്കുന്നവയിൽ ശരിയല്ലാത്തത് ഏത്

  1. (a+b)² = a² + 2ab + b²
  2. a²-b² = (a+b)(a-b)
  3. a³-b³=(a-b)³ +3ab(a-b)
  4. a³+b³=(a+b)³ +3ab(a+b)