Question

Mr. Bajaj and his son start from their home with speeds of 12 km/h and 18 km/h respectively and reach movie theatre. If his son leaves 60 min after his father from home and reaches movie theatre, 60 min before his father, what is the distance between their home and the movie theatre?

• A. 60 km
• B. 72 km
• C. 48 km
• D. 75 km

Answer 1

Answer:

B. 72 km

Distance = (S1 × S2)/(S1 - S2) × (Time difference) S1 and S2 are the two speeds, ⇒ (12 × 18)/(18 - 12) × 2 = (12 × 18)/6 × 2 = 72 km