Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers. It is given that 7A3 is exactly divisible by 3. The only possible value of B is
A2
B5
C7
D8
Answer:
D. 8
Read Explanation:
Solution:
Concept:
The divisibility rule of 3 states that a number is completely divisible by 3 if the sum of its digit is divisible by 3 or multiple of 3.
Calculation:
⇒ 7 + A + 3 = 10 + A (Possible value of A is 2, 5, 8)
⇒ 136 + 5B7 = 7A3 (Possible value of B is 6, 7, 8, 9)
⇒ For A = 2, B = 8
⇒ 7 + 2 + 3 = 12, (Which is divisible by 3 or multiple of 3)
⇒ The value of B = 8
∴ The required result will be 8.
