Question

Out of five numbers A, B, C, D and E, the average of the first four numbers A, B, C and D is greater than the average of the last four numbers B, C, D and E by 35. Find the differences between A and E.

• A. 80
• B. 120
• C. 130
• D. 140

Answer 1

Answer:

D. 140

Solution: Given: Five numbers are A, B, C, D and E The average of the first four numbers A, B, C and D is greater than the average of the last four numbers B, C, D and E by 35 Formula used: Average = the sum of observations/the number of observation Calculation: The average of the first four numbers = (A + B + C + D)/4 The average of the last four numbers = (B + C + D + E)/4 According to the question, The average of the first four numbers - The average of the last four numbers = 35 ⇒ (A + B + C + D)/4 - (B + C + D + E)/4 = 35 ⇒ (A + B + C + D - B - C - D - E)/4 = 35 ⇒ (A - E)/4 = 35 ⇒ (A - E) = 35 × 4 ⇒ A - E = 140 ∴ The difference between A and E is 140