If $\overset{\rightarrow}{r(t)}=tan^{-1}ti+sintj+t^2k$, then $\overset{\rightarrow}{r'(t)}

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$\overset{\rightarrow}{r(t)}=tan^{-1}ti+sintj+t^2k$ ആയാൽ $\overset{\rightarrow}{r'(t)}_{t=0}=$

Ai-j

B1/2i+j+k

Ci+j-k

Di+j

Answer:

D. i+j

Read Explanation:

$\overset{\rightarrow}{r'(t)}=\frac{1}{1+t^2}i+costj +2tk$

$\overset{\rightarrow}{r'(t)}_{t=0}=\frac{1}{1+0}i+cos0+2 \times 0k$

$=i+j$

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