9x+3x−90=09^x+3^x-90=09x+3x−90=0എങ്കിൽ x എത്ര ? A3B6C4D2Answer: D. 2 Read Explanation: 9x+3x−90=09^x+3^x-90=09x+3x−90=032x+3x−90=03^{2x}+3^x-90=032x+3x−90=032x+3x=903^{2x}+3^x=9032x+3x=903x(32+1)=903^x(3^2+1)=903x(32+1)=903x×(9+1)=903^x\times(9+1)=903x×(9+1)=903x=90/10=93^x = 90/10 = 93x=90/10=93x=323^x=3^23x=32x=2x=2x=2 Read more in App