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2102^{10} നോടു എത്ര കൂട്ടിയാൽ 2112^{11} ലഭിക്കും 

A$2^1$

B$2^{10}$

C$2^0$

D$2^{11}$

Answer:

$2^{10}$

Read Explanation:

211=210+X2^{11}=2^{10}+X

X=211210X=2^{11}-2^{10}

=210[21]=2^{10}[2-1]

X=210X=2^{10}


Related Questions:

a/(a)×(a)/a2×a3=?a/(\sqrt{a})\times(\sqrt{a})/a^2\times{a^3}=?

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(323+2)+(3+232)= (\frac {\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}})+(\frac {\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}) =

The value of 256+0.01214.41\sqrt{256}+\sqrt{0.0121}-\sqrt{4.41}
1¼ ൻ്റെ വർഗ്ഗം കാണുക.