App Logo

No.1 PSC Learning App

1M+ Downloads

21002^{100} ന്റെ പകുതി എത്ര?

A2^50

B2^99

C2^98

D2^101

Answer:

B. 2^99

Read Explanation:

2100/22^{100}/2

aman=amn\because{\frac{a^m}{a^n}}=a^{m-n}

= 210012^{100-1}

= 2992^{99}

 


Related Questions:

(3/5)x(3/5)^x= 81/625 ആണെങ്കിൽ, xxx^x ൻ്റെ മൂല്യം എന്ത്?

image.png
image.png

2m=162^m = 16 ആയാൽ 3(m1)3^{(m -1)} എത്ര ?

The grad • at the point (1.-2.-1) for ^ (x, y, z) = 3x²y-y³z² is