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2x+42x+2=32^{x+4}-2^{x+2}=3

ആയാൽ x ന്റെ വില കണ്ടെത്തുക 

A2

B-2

C3

D-3

Answer:

B. -2

Read Explanation:

2x+42x+2=32^{x+4}-2^{x+2}=3

2x+2+22x+2=32^{x+2+2}-2^{x+2}=3

2x+2[221]=32^{x+2}[2^{2}-1]=3
2x+2[41]=32^{x+2}[4-1]=3
2x+2×3=32^{x+2}\times3=3
2x+2=3/3=12^{x+2}=3/3=1
2x+2=202^{x+2}=2^0
x+2=0x+2=0
x=2x=-2


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(23+34+45)0=(2^3+3^4+4^5)^0=

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