2x+4−2x+2=32^{x+4}-2^{x+2}=32x+4−2x+2=3 ആയാൽ x ന്റെ വില കണ്ടെത്തുക A2B-2C3D-3Answer: B. -2 Read Explanation: 2x+4−2x+2=32^{x+4}-2^{x+2}=32x+4−2x+2=3 2x+2+2−2x+2=32^{x+2+2}-2^{x+2}=32x+2+2−2x+2=3 2x+2[22−1]=32^{x+2}[2^{2}-1]=32x+2[22−1]=32x+2[4−1]=32^{x+2}[4-1]=32x+2[4−1]=32x+2×3=32^{x+2}\times3=32x+2×3=32x+2=3/3=12^{x+2}=3/3=12x+2=3/3=12x+2=202^{x+2}=2^02x+2=20x+2=0x+2=0x+2=0x=−2x=-2x=−2 Read more in App