Question

A ball is thrown up with an initial velocity of 20 m/s and after some time it returns. What is the maximum height reached? Take g = $10 m/s^2$.

• A. 80m
• B. 20m
• C. 70m
• D. 40m

Answer 1

Answer:

B. 20m

$v^2 = u^2 + 2as$

At the maximum height, the velocity of the ball will be zero, therefore, v = 0, u = 20, and a = -g = -10. s = 20m.