Question

$\frac{\sqrt{32}+\sqrt{48}}{\sqrt8+\sqrt{12}}=?$

• A. √2
• B. 4
• C. 2
• D. 8

Answer 1

Answer:

C. 2

$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}=\frac{4\sqrt{2}+4\sqrt3}{2\sqrt2+2\sqrt3}$

$=\frac{2(2\sqrt2+2\sqrt3)}{2\sqrt2+2\sqrt3}$

$=2$