$\sqrt{(2^2)^2+2(2^{-1})+((2^{10})^{\frac{1}{2}})}$ =

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$\sqrt{(2^2)^2+2(2^{-1})+((2^{10})^{\frac{1}{2}})}$ =

A6

B$\sqrt20$

C$\sqrt48$

D7

Answer:

D. 7

Read Explanation:

$2^4$ +(2x $\frac12$ )+ $2^5$ =16+1+32 = $\sqrt{49}$ =7

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