(22)2+2(2−1)+((210)12)\sqrt{(2^2)^2+2(2^{-1})+((2^{10})^{\frac{1}{2}})}(22)2+2(2−1)+((210)21) = A6B$\sqrt20$C$\sqrt48$D7Answer: D. 7 Read Explanation: 242^424+(2x12\frac1221)+252^525 =16+1+32 =49\sqrt{49}49 =7 Read more in App