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പഞ്ചഭുജം : 108 : : നവഭുജം :

A120°

B150°

C130°

D140°

Answer:

D. 140°

Read Explanation:

n വശങ്ങളുള്ള ഒരു ബഹുഭുജത്തിന്റെ ആന്തരകോണുകളുടെ തുക

=(n-2)180°

നവഭുജത്തിന്റെ ആന്തരകോണുകളുടെ തുക

=(9 - 2)180°

= 7 × 180°

= 1260°

നവഭുജത്തിന്റെ ഒരു ആന്തരകോണിന്റെ അളവ്

= 1260/9

= 140°


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