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Rakesh is standing at a point. He walks 20 m towards east and further 10 m towards south. He then walks 35 m towards west and further 5 m towards north. Again he walks 15 m towards east. What is the shortest distance in meters between his starting point and the point where he is now?

A5 m

BCannot be determined

C10 m

D1 m

Answer:

A. 5 m

Read Explanation:

1. Visualize the Movements

It's helpful to visualize Rakesh's movements on a coordinate plane. Let's assume his starting point is (0, 0).

  • East: Movement to the right (positive x-axis)

  • West: Movement to the left (negative x-axis)

  • North: Movement upwards (positive y-axis)

  • South: Movement downwards (negative y-axis)

2. Track the Net Movements

  • East/West:

    • 20 m East + 35 m West + 15 m East = 20 + (-35) + 15 = 0 m

    • Net change in East/West direction = 0 m

  • North/South:

    • 10 m South + 5 m North = -10 + 5 = -5 m

    • Net change in North/South direction = -5 m (which means 5 m South)

3. Determine the Final Position

  • Rakesh's net movement is 0 meters in the East/West direction and 5 meters in the South direction.

  • So, his final position is 5 meters South of his starting point.

4. Calculate the Shortest Distance

  • Since there's no East/West movement, the shortest distance is simply the net movement in the North/South direction.

  • Shortest distance = 5 meters


Related Questions:

Abhay travelled 9 km Northwards, turned left and travelled 5 km, then turned left again and travelled 9 km. How far is Abhay from the starting point?
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