Question

Refer to the given number series and answer the question that follows. Counting to be done from left to right only.

(Left) 4 3 5 6 2 1 5 5 7 1 5 2 3 6 9 7 4 7 9 5 8 5 3 7 4 2 1 (Right) .

How many such odd digits are there each of which is immediately preceded by an even digit and also immediately followed by an even digit?

• A. 2
• B. 1
• C. 3
• D. 4

Answer 1

Answer:

B. 1

There is only 1 such odd digit in the series.

We need to find the pattern: Even Digit $\rightarrow$ Odd Digit $\rightarrow$ Even Digit.

Let's check the sequence from left to right:

• 4 3 5: Even $\rightarrow$ Odd $\rightarrow$ Odd (No)

• 2 1 5: Even $\rightarrow$ Odd $\rightarrow$ Odd (No)

• 2 3 6: Even $\rightarrow$ Odd $\rightarrow$ Even (Yes! This matches the pattern 2 3 6)

• 6 9 7: Even $\rightarrow$ Odd $\rightarrow$ Odd (No)

• 4 7 9: Even $\rightarrow$ Odd $\rightarrow$ Odd (No)

• 8 5 3: Even $\rightarrow$ Odd $\rightarrow$ Odd (No)

Matching Group

• 2 3 6 (The odd digit is 3)