2 people sit between Q and E when counted from the right of E.
1. S sits third to the left of P: Place P at the bottom (position 1). Counting 3 places to the left (clockwise), place S at position 4.
2. C sits to the immediate left of P: Since everyone faces the centre, immediate left of P means moving 1 place clockwise. Place C next to P at position 2.
3. Only R sits between D and S: We know S is at position 4. Its neighbors are positions 3 and 5. Position 3 is next to C (position 2), and position 5 is on the other side. Since R must be between D and S, they must fill positions 3 and 5.
4. E is not an immediate neighbour of S: S is at position 4. The remaining empty spots for E are positions 6 and 7. Since E cannot be next to S (ruling out position 5), R must be at position 5 and D must be at position 6.
5. Placing E and Q: Now positions 3 and 7 are left. Since position 3 is next to S, E cannot sit there. So E must sit at position 7. This leaves position 3 for Q.
The Final Circle Order (Clockwise)
• Position 1: P
• Position 2: C
• Position 3: Q
• Position 4: S
• Position 5: R
• Position 6: D
• Position 7: E
Finding the Answer
Counting from the right of E (counter-clockwise direction from position 7):
• The sequence goes from E → P → C →Q.
• The people sitting between E and Q are P and C.
Therefore, there are exactly 2 people between them.