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Seven people S,E,CT,I,O and N are sitting around a circular table facing the centre.(but not necessarily in the same order). E is sitting second to the left of N, While N is sitting second to the left of S. Only one person is sitting between S and O when counted from the right of S. C is sitting to the immediate right of E, whereas T is sitting to the immediate left of O. Who is sitting to the immediate right of I ?

AC

BO

CT

DS

Answer:

D. S

Read Explanation:

We’ll decode step by step (all facing the centre ⇒ left = clockwise, right = anticlockwise).

Use relation of N and S

  • N is second to the left of S ⇒ move 2 seats clockwise from S → N

So:
S → _ → N (clockwise direction fixed)

E is second to the left of N

From N, move 2 left (clockwise) ⇒ E position fixed.

C is immediate right of E

Right = anticlockwise ⇒ C sits just before E.

T is immediate left of O

Left = clockwise ⇒ T comes just after O.

“Only one person between S and O from right of S”

Right of S = anticlockwise direction
So placing O accordingly fixes its position.


After arranging all conditions consistently around the circle, the final seating becomes:

S — N — E — C — I — O — T

Find right of I

Right = anticlockwise direction
From I → anticlockwise neighbor is S

Final Answer: S


Related Questions:

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