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Simplify 1.24‾1.\overline{24} as an improper fraction.

A123/90

B41/33

C91/90

D124/99

Answer:

B. 41/33

Read Explanation:

The final simplified value is 4133\frac{41}{33}.

1: Write the repeating decimal as an equation

Let x=1.242424...x = 1.242424... — (Equation 1)

2: Multiply to shift the repeating block

Since there are two repeating digits under the bar (2 and 4), multiply both sides of the equation by 100:
100x=124.242424...100x = 124.242424... — (Equation 2)

3: Subtract Equation 1 from Equation 2

Subtracting the equations eliminates the infinite repeating decimal part:
100x−x=124.242424...−1.242424...100x - x = 124.242424... - 1.242424...
99x=12399x = 123

4: Solve for xx and reduce to lowest terms

x=12399x = \frac{123}{99}

Divide both the numerator and the denominator by their greatest common divisor, which is 3:

  • 123÷3=41123 \div 3 = 41

  • 99÷3=3399 \div 3 = 33

This gives the final improper fraction: 4133\frac{41}{33}.


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