Let’s solve it systematically, step by step.
Six friends: E, F, G, R, S, T
They sit around a circular table facing the centre
So right = clockwise, left = anticlockwise
Fix a reference point
In circular seating, we can fix anyone anywhere.
Place F anywhere (for convenience).
Use positional clues
S sits second to the right of F
→ Move 2 seats clockwise from F → place S
F sits second to the right of G
→ Move 2 seats clockwise from G → reach F
→ So G is second to the left of F
Now we have (clockwise):
G F S _
(6 seats total)
Use “Only F sits between R and E”
The two seats next to F are already:
One side → G
Other side → empty
So G cannot be R or E
Thus, R and E must occupy the two seats with F in between, meaning:
Arrangement must be: R – F – E (clockwise or anticlockwise)
But remember:
So E must be next to S.
Place E correctly
From earlier layout:
G F S _
The only way E can be adjacent to S and adjacent to F is:
Clockwise order becomes:
G – R – F – E – S – T
(T is the remaining person)
Final seating (clockwise)
Position | Person |
|---|
1 | G |
2 | R |
3 | F |
4 | E |
5 | S |
6 | T |
All conditions satisfied
Question asked
How many people sit between T and R when counted from the right of R?
Path:
R → F → E → S → T
People between R and T:
3 people sit between T and R when counted from the right of R.