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Six friends E, F, G, R, S and T are sitting around a circular table facing the centre (but not necessarily in the same order). S sits second to the right of F. F sits second to the right of G. Only F sits between R and E. E is an immediate neighbour of S. How many people sit between T and R when counted from the right of R?

AFour

BOne

CThree

DTwo

Answer:

C. Three

Read Explanation:

Let’s solve it systematically, step by step.

Six friends: E, F, G, R, S, T
They sit around a circular table facing the centre
So right = clockwise, left = anticlockwise

Fix a reference point

In circular seating, we can fix anyone anywhere.

Place F anywhere (for convenience).

Use positional clues

  1. S sits second to the right of F
    → Move 2 seats clockwise from F → place S

  2. F sits second to the right of G
    → Move 2 seats clockwise from G → reach F
    → So G is second to the left of F

Now we have (clockwise):

G F S _

(6 seats total)

Use “Only F sits between R and E”

  • This means R – F – E or E – F – R

  • So R and E are adjacent to F, with F exactly between them

The two seats next to F are already:

  • One side → G

  • Other side → empty

So G cannot be R or E
Thus, R and E must occupy the two seats with F in between, meaning:

Arrangement must be: R – F – E (clockwise or anticlockwise)

But remember:

  • E is an immediate neighbour of S

So E must be next to S.

Place E correctly

From earlier layout:
G F S _

The only way E can be adjacent to S and adjacent to F is:

Clockwise order becomes:
G – R – F – E – S – T

(T is the remaining person)

Final seating (clockwise)

Position

Person

1

G

2

R

3

F

4

E

5

S

6

T

All conditions satisfied

Question asked

How many people sit between T and R when counted from the right of R?

  • Right of R = clockwise

  • Starting from R → move right toward T

Path:
R → F → E → S → T

People between R and T:

  • F, E, S → 3 people

3 people sit between T and R when counted from the right of R.


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