Question

$\sqrt{30\frac25+23\frac{3}{10}+?}=(2\sqrt{2})^2$

So what is the number in the n's place?

• A. 10 ³/10
• B. 8⅘
• C. 10 ⁷/10
• D. 7⅖

Answer 1

Answer:

A. 10 ³/10

$\sqrt{30\frac25+23\frac{3}{10}+?}=(2\sqrt{2})^2$

$\sqrt{\frac{152}{5}+\frac{233}{10}+?}=8$

$\sqrt{\frac{304+233}{10}+?}=8$

$\frac{537}{10}+?=8^2=64$

$?=64-\frac{537}{10}$

$=\frac{640-537}{10}$

$=\frac{103}{10}$

$=10\frac{3}{10}$