Question

Steel column pinned at both ends has a modulus of elasticity $E = 2 \times 10^5 N/mm^2$, moment of inertia I = 90000mm, L = 1.75 m, value of Euler's critical load will be

• A. 75000 N
• B. 72000 N
• C. 68000 N
• D. 58009 N

Answer 1

Answer:

D. 58009 N

Given: $E = 2 \times 10 ^ 5 N / m m ^ 2$ $I_{min} =90000 mm^ 4$ , $L = 1.75m$ , The Euler's buckling load for the column pinned at both ends: $P_e = \frac{\pi ^ 2 E I_{min}}{ L^ 2}$ ;$P_{e} =\frac {pi ^ 2 \times 2 \times 10 ^ 5 \times 9000}{(1.75 \times 1000) ^ 2} = 58009.1N$