(-1)^25 + (-1)^50 – (-1)^20 / 1^0 ?

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$(-1)^{25} + (-1)^{50}- (-1)^{20} / 1^0 =?$

A-1

Dഇവയൊന്നുമല്ല

Answer:

$(-1)^{25} = -1$

$(-1)^{50} = 1$

$(-1)^{20} = 1$

$1^0 = 1$

$-1+1-1/1=-1$

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