If x=12x = \frac12x=21 and y=13y = \frac13y=31, then what is x+yxy \frac{x+y}{xy}xyx+y? A5B3C6D2Answer: A. 5 Read Explanation: x+y=12+13 x+y = \frac12+\frac13x+y=21+31 =56= \frac56=65xy=16 xy = \frac16xy=61x+yxy=5\frac{x+y}{xy} = 5xyx+y=5 Read more in App