What is the value of (3/5)2×(5/7)−23/5)3×(7/5)2=?\frac{(3/5)^2\times(5/7)^{-2}}{3/5)^3\times(7/5)^2}=?3/5)3×(7/5)2(3/5)2×(5/7)−2=? A3/5B7/3C3/7D5/3Answer: D. 5/3 Read Explanation: (3/5)2×(5/7)−2(3/5)3×(7/5)2\frac{(3/5)^2\times(5/7)^{-2}}{(3/5)^3\times(7/5)^2}(3/5)3×(7/5)2(3/5)2×(5/7)−2=(3/5)2×(5/7)−2×(5/3)3×(5/7)2=(3/5)^2\times(5/7)^{-2}\times(5/3)^3\times(5/7)^2=(3/5)2×(5/7)−2×(5/3)3×(5/7)2=5/3=5/3=5/3 Read more in App