$1\frac38\times3$

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$1\frac38\times3$

A $3\frac{8}{11}$

B $1\frac38$

C $1\frac48$

D $4\frac18$

Answer:

4\frac18

$1\frac38\times3$

$=\frac{11}{8}\times3$

$=\frac{33}{8}$

$=4\frac18$

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If $\frac{(2a+b)}{(a+4b)}=3$ , then find the value of $\frac{a+b}{a+2b}$

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