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ABCD is a rectangle, where AB = 4 cm and AD = 2 cm. Two arcs are drawn of radius AD and BC respectively. What is the area of the shaded region?

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A4π4 – π cm^2$$

B8π8 – π cm^2$$

C42π4 – 2π cm^2$$

D82π8 – 2π cm^2$$

Answer:

82π8 – 2π cm^2$$

Read Explanation:

Given:

⇒ Length of the rectangle = 4 cm

⇒ Breadth of the rectangle = 2 cm

Calculation:

∴ Area of the rectangle = 4×2=8cm24\times{2}=8cm^2

⇒ Area of the arc having radius AD,

14×π×22⇒\frac{1}{4}\times{π}\times{22}

πcm2⇒πcm^2

⇒ Area of the arc having radius BC,

14×π×22⇒\frac{1}{4}\times{π}\times{22}

πcm2⇒πcm^2

∴ Area of the shaded region,

⇒8-2π cm2cm^2


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