Question

Find the zero of the polynomial :$p(x)=2x^2+13x-7$

• A. -7
• B. $$\frac{3}{4}$$
• C. $$\frac{2}{13}$$
• D. $$\frac{1}{2}$$

Answer 1

Answer:

$$\frac{1}{2}$$

$p(x)=2x^2+13x-7$

To find the zero of the polynomial $p(x)=0$

$p(x)=2x^2+13x-7=0$

$2x^2+14x-1x-7=0$

$2x(x+7)-1(x+7)=0$

$(2x-1)(x+7)=0$

either(2x-1)=0 or (x + 7) = 0

If $2x - 1 = 0$

$2x-1=0$

$2x=1$

$x=1/2$

If x + 7 = 0

$x + 7=0$

$x= -7$

root of polynomial is always positive

so here root = $\frac{1}{2}$.