App Logo

No.1 PSC Learning App

1M+ Downloads

10x×45x=28\frac{10^x \times 4}{5^x}=2^8 ആയാൽ x-ന്ടെ വില എത്ര?

A4

B2

C3

D6

Answer:

D. 6

Read Explanation:

10x×45x=28\frac{10^x \times 4}{5^x}=2^8

(2×5)x×225x=28\frac{(2 \times 5)^x \times 2^2}{5^x}=2^8

2x×5x×225x=28\frac{2^x \times 5^x \times 2^2}{5^x}=2^8

2x+2=282^{x+2}=2^8

x+2=8x+2=8

x=6x=6


Related Questions:

Find the reminder when 31013^{101} is divided by 7?

2x+1=8x2^{x+1} =8^{x} ആയാൽ x ന്റെ വില എത്ര?

4n=128;4n+24^n=128;4^{n+2}എത്ര?

a1+1a+1=?\frac{a^{-1}+1}{a+1}=?

(1)100+(1)101=?(-1)^{100} + (-1)^{101} =?