If f(x)=∣x+a x+2 x+1x+b x+3 x+2x+c x+4 x+3∣f(x) = \begin{vmatrix} x+a \ \ \ x+2 \ \ \ x+1\\ x+b \ \ \ x+3 \ \ \ x+2 \\ x+c \ \ \ x+4 \ \ \ x+3\end{vmatrix}f(x)=∣∣x+a x+2 x+1x+b x+3 x+2x+c x+4 x+3∣∣ ; a-2b+c= 1 ആണെങ്കിൽ, Af(50)=1Bf(50)=-1Cf(50)=501Df(50)=-501Answer: A. f(50)=1 Read Explanation: .Read more in App