If ab=cd=5\frac{a}{b}=\frac{c}{d}=5ba=dc=5, then 3a+4c3b+4d\frac{3a+4c}{3b+4d}3b+4d3a+4c is equal to? A60B15C5D20Answer: C. 5 Read Explanation: Soltion:Given; ab=cd=5\frac{a}{b}=\frac{c}{d}=5ba=dc=5Let a=c=5andb=d=1a=c=5 and b= d= 1a=c=5andb=d=1To Find: 3a+4c3b+4d\frac{3a+4c}{3b+4d}3b+4d3a+4c =3(5)+4(5)3(1)+4(1)=\frac{3(5)+4(5)}{3(1)+4(1)}=3(1)+4(1)3(5)+4(5)=15+207=\frac{15+20}{7}=715+20=357=5=\frac{35}{7}=5=735=5Hence the answer is option(C). Read more in App