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If ab=cd=5\frac{a}{b}=\frac{c}{d}=5, then 3a+4c3b+4d\frac{3a+4c}{3b+4d} is equal to?

A60

B15

C5

D20

Answer:

C. 5

Read Explanation:

Soltion:

Given; ab=cd=5\frac{a}{b}=\frac{c}{d}=5

Let a=c=5andb=d=1a=c=5 and b= d= 1

To Find: 3a+4c3b+4d\frac{3a+4c}{3b+4d}

=3(5)+4(5)3(1)+4(1)=\frac{3(5)+4(5)}{3(1)+4(1)}

=15+207=\frac{15+20}{7}

=357=5=\frac{35}{7}=5

Hence the answer is option(C).


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