limx→2[x3−2x2x2−5x+6]=\lim_{x \to 2} [\frac{x^3 - 2x^2}{x^2-5x+6}]=limx→2[x2−5x+6x3−2x2]= A-2B-4C2D4Answer: B. -4 Read Explanation: limx→2[x3−2x2x2−5x+6]\lim_{x \to 2} [\frac{x^3 - 2x^2}{x^2-5x+6}]limx→2[x2−5x+6x3−2x2]limx→2[x3−2x2x2−5x+6]=limx→2x2(x−2)(x−2)(x−3)=limx→2x2x−3=4−1=−4\lim_{x \to 2} [\frac{x^3 - 2x^2}{x^2-5x+6}]= \lim_{x \to 2}\frac {x^2(x-2)}{(x-2)(x-3)} = \lim_{x \to 2} \frac{x^2}{x-3} = \frac{4}{-1}= -4limx→2[x2−5x+6x3−2x2]=limx→2(x−2)(x−3)x2(x−2)=limx→2x−3x2=−14=−4 Read more in App
