App Logo

No.1 PSC Learning App

1M+ Downloads

p(x)=2x2+3x+7p(x) =2x^2+3x+7,q(x)=6x2+8x9q(x)=6x^2+8x-9Find p(x)×q(x)p(x)\times{q(x)}

A12x4+32x3+49x2+28x6312x^4+32x^3+49x^2+28x-63

B12x4+36x3+39x2+31x6312x^4+36x^3+39x^2+31x-63

C12x4+34x3+46x2+27x6312x^4+34x^3+46x^2+27x-63

D12x4+34x3+48x2+29x6312x^4+34x^3+48x^2+29x-63

Answer:

12x4+34x3+48x2+29x6312x^4+34x^3+48x^2+29x-63

Read Explanation:

p(x)=2x2+3x+7p(x) =2x^2+3x+7,q(x)=6x2+8x9q(x)=6x^2+8x-9

p(x)×q(x)=2x2[6x2+8x9]+3x[6x2+8x9]+7[6x2+8x9]p(x)\times{q(x)}=2x^2[6x^2+8x-9]+3x[6x^2+8x-9]+7[6x^2+8x-9]

=12x4+16x318x2+18x3+24x227x+42x2+56x63=12x^4+16x^3-18x^2+18x^3+24x^2-27x+42x^2+56x-63

=12x4+34x3+48x2+29x63=12x^4+34x^3+48x^2+29x-63


Related Questions:

Find the degree of the polynomial : x4+x2+1=0x^4 + x^2 + 1 = 0
image.png

Find the value of k if x - 1 is a factor of 4x3+3x2+4x+k4x^3+3x^2+4x+k

Simplify: 3x(x - 6) + x² + 6x - 9 + 24 - x³
In polynomial P(x) = ax³ + bx² + cx + d, P(1) =P(-1), find a + c