$p(x) =2x^2+3x+7$,$q(x)=6x^2+8x-9$Find q(x)-p(x)

Challenger App

No.1 PSC Learning App

★

★

★

★

★

1M+ Downloads

$p(x) =2x^2+3x+7$ , $q(x)=6x^2+8x-9$ Find q(x)-p(x)

A $8x^2+11x-2$

B $4x^2+5x+16$

C $-4x^2-5x+16$

D $4x^2+5x-16$

Answer:

4x^2+5x-16

Read Explanation:

$p(x) =2x^2+3x+7$

$q(x)=6x^2+8x-9$

$q(x)-p(x)=x^2(6-2)+x(8-3)+(-9-7)$

$=4x^2+5x-16$

Read more in App

Related Questions:

The product of the roots of 3x² - 13x + 6 = 0 is:

The equation $(x-2)^2+1=2x-3$ is:

6(x ^ 3 - 2x ^ 2 + 3x) - (x ^ 3 + 2x - 3)