2025+30310+x=(22)2\sqrt{20\frac25+30\frac{3}{10}+x}=(2\sqrt{2})^22052+30103+x=(22)2$$ആയാൽ x ൻ്റെ വില എത്ര? A1010310\frac{10}{3}10310B1331013\frac{3}{10}13103C310133\frac{10}{13}31310Dഇവയൊന്നും അല്ലAnswer: 1331013\frac{3}{10}13103 Read Explanation: 2025+30310+x=(22)2\sqrt{20\frac25+30\frac{3}{10}+x}=(2\sqrt{2})^22052+30103+x=(22)22025+30310+x=8\sqrt{20\frac25+30\frac{3}{10}+x}=82052+30103+x=82025+30310+x=82=6420\frac25+30\frac{3}{10}+x= 8^2=642052+30103+x=82=6420+30+2/5+3/10+x=6420+30+2/5+3/10+x=6420+30+2/5+3/10+x=6450+7/10+x=6450+7/10+x=6450+7/10+x=64x=64−50−7/10x=64-50-7/10x=64−50−7/10x=14−7/10x=14-7/10x=14−7/10x=(140−7)/10x=(140-7)/10x=(140−7)/10x=133/10x=133/10x=133/10x=13310x=13\frac{3}{10}x=13103 Read more in App