The value of 0.16ˉ+0.15ˉ−0.13ˉ0.1\bar{6}+0.1\bar{5}-0.1\bar{3}0.16ˉ+0.15ˉ−0.13ˉ is: A1790\frac{17}{90}9017B3435\frac{34}{35}3534C2363\frac{23}{63}6323D1999\frac{19}{99}9919Answer: 1790\frac{17}{90}9017 Read Explanation: 0.16ˉ+0.15ˉ−0.13ˉ0.1\bar{6}+0.1\bar{5}-0.1\bar{3}0.16ˉ+0.15ˉ−0.13ˉ0.16ˉ=0.16666...0.1\bar{6}=0.16666...0.16ˉ=0.16666...x=0.16666.....x=0.16666.....x=0.16666.....10x=1.66666...10x=1.66666...10x=1.66666...10x−x=1.510x-x=1.510x−x=1.59x=1.59x =1.59x=1.5x=1.59x=\frac{1.5}{9}x=91.5Similarly,0.15ˉ=1.490.1\bar{5}=\frac{1.4}{9}0.15ˉ=91.40.13ˉ=1.290.1\bar{3}=\frac{1.2}{9}0.13ˉ=91.20.16ˉ+0.15ˉ−0.13ˉ=1.59+1.49−1.290.1\bar{6}+0.1\bar{5}-0.1\bar{3}=\frac{1.5}{9}+\frac{1.4}{9}-\frac{1.2}{9}0.16ˉ+0.15ˉ−0.13ˉ=91.5+91.4−91.2=1.5+1.4−1.29=1.79=\frac{1.5+1.4-1.2}{9}=\frac{1.7}{9}=91.5+1.4−1.2=91.7=1790=\frac{17}{90}=9017 Read more in App